What are the solutions to the equation 2x^2-20x=8 ?

The solutions to the equation 2x^2-20x=8 are x=5+sqrt(29),x=5-sqrt(29)

Find the zeros of 2x^2-20x=8

The zeros of 2x^2-20x=8 are x=5+sqrt(29),x=5-sqrt(29)

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2 x^{2} - 20 x = 8

x = 5 + 29, x = 5 - 29

Decimal Notation

x = 10.38516 \dots, x = - 0.38516 \dots

Solution steps

2 x^{2} - 20 x = 8

Move

8

to the left side

2 x^{2} - 20 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 20)^{2} - 4 \cdot 2 (- 8) = 429

x_{1, 2} = \frac{- ( - 20 ) \pm 4 29}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 29}{2 \cdot 2}, x_{2} = \frac{- ( - 20 ) - 4 29}{2 \cdot 2}

x = \frac{- ( - 20 ) + 4 29}{2 \cdot 2} : 5 + 29

x = \frac{- ( - 20 ) - 4 29}{2 \cdot 2} : 5 - 29

The solutions to the quadratic equation are:

x = 5 + 29, x = 5 - 29

4 y^{2} + 16 = 0

x^{2} - 4 x + 4 = \frac{3}{2} x - 2

- 12 x^{2} + 60 x = 0

x^{2} - 9 = 5 (x - 3)

1 1^{2} + 6 0^{2} = c^{2}

What are the solutions to the equation 2x^2-20x=8 ?
The solutions to the equation 2x^2-20x=8 are x=5+sqrt(29),x=5-sqrt(29)
Find the zeros of 2x^2-20x=8
The zeros of 2x^2-20x=8 are x=5+sqrt(29),x=5-sqrt(29)