What are the solutions to the equation r^2+r-56=0 ?

The solutions to the equation r^2+r-56=0 are r=7,r=-8

Find the zeros of r^2+r-56=0

The zeros of r^2+r-56=0 are r=7,r=-8

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r^{2} + r - 56 = 0

r = 7, r = - 8

Solution steps

r^{2} + r - 56 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 56) = 15

r_{1, 2} = \frac{- 1 \pm 15}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 1 + 15}{2 \cdot 1}, r_{2} = \frac{- 1 - 15}{2 \cdot 1}

r = \frac{- 1 + 15}{2 \cdot 1} : 7

r = \frac{- 1 - 15}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

r = 7, r = - 8

r^{2} = - 36

24 (x + 4) (x + 3) - 24 (x + 2) (x + 5) = (x + 5) (x + 3)

x^{2} - 18 + 56 = 0

x^{2} + x - 1 = 0

0 = 3 t^{2} - 12 t + 9

What are the solutions to the equation r^2+r-56=0 ?
The solutions to the equation r^2+r-56=0 are r=7,r=-8
Find the zeros of r^2+r-56=0
The zeros of r^2+r-56=0 are r=7,r=-8