What are the solutions to the equation 3x^2-4x=9 ?

The solutions to the equation 3x^2-4x=9 are x=(2+sqrt(31))/3 ,x=(2-sqrt(31))/3

Find the zeros of 3x^2-4x=9

The zeros of 3x^2-4x=9 are x=(2+sqrt(31))/3 ,x=(2-sqrt(31))/3

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3 x^{2} - 4 x = 9

x = \frac{2 + 31}{3}, x = \frac{2 - 31}{3}

Decimal Notation

x = 2.52258 \dots, x = - 1.18925 \dots

Solution steps

3 x^{2} - 4 x = 9

Move

9

to the left side

3 x^{2} - 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 9) = 231

x_{1, 2} = \frac{- ( - 4 ) \pm 2 31}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 31}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 31}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 31}{2 \cdot 3} : \frac{2 + 31}{3}

x = \frac{- ( - 4 ) - 2 31}{2 \cdot 3} : \frac{2 - 31}{3}

The solutions to the quadratic equation are:

x = \frac{2 + 31}{3}, x = \frac{2 - 31}{3}

(2 x + 1)^{2} = 32

x, (x - y)^{2} = 0

- x^{2} + 10 x + 70 = 0

0 = 3 x^{2} - 2 x - 10

- 3 (2 x - 16) (x + 7) = 0

What are the solutions to the equation 3x^2-4x=9 ?
The solutions to the equation 3x^2-4x=9 are x=(2+sqrt(31))/3 ,x=(2-sqrt(31))/3
Find the zeros of 3x^2-4x=9
The zeros of 3x^2-4x=9 are x=(2+sqrt(31))/3 ,x=(2-sqrt(31))/3