What are the solutions to the equation 5p^2+10p-49=-9 ?

The solutions to the equation 5p^2+10p-49=-9 are p=2,p=-4

Find the zeros of 5p^2+10p-49=-9

The zeros of 5p^2+10p-49=-9 are p=2,p=-4

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5 p^{2} + 10 p - 49 = - 9

p = 2, p = - 4

Solution steps

5 p^{2} + 10 p - 49 = - 9

Move

9

to the left side

5 p^{2} + 10 p - 40 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 ( - 40 )}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 (- 40) = 30

p_{1, 2} = \frac{- 10 \pm 30}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- 10 + 30}{2 \cdot 5}, p_{2} = \frac{- 10 - 30}{2 \cdot 5}

p = \frac{- 10 + 30}{2 \cdot 5} : 2

p = \frac{- 10 - 30}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

p = 2, p = - 4

x^{2} = x + 72

5 x^{2} + 5 x - 7 = 0

(2 k + 2) x^{2} - 4 x + k = 0

60 x^{2} + 4.75 x - 58.8 = 0

15 x^{2} - 26 x - 21 = 0

What are the solutions to the equation 5p^2+10p-49=-9 ?
The solutions to the equation 5p^2+10p-49=-9 are p=2,p=-4
Find the zeros of 5p^2+10p-49=-9
The zeros of 5p^2+10p-49=-9 are p=2,p=-4