What are the solutions to the equation 6e^2+9=4e ?

The solutions to the equation 6e^2+9=4e are e= 1/3+i(5sqrt(2))/6 ,e= 1/3-i(5sqrt(2))/6

Find the zeros of 6e^2+9=4e

The zeros of 6e^2+9=4e are e= 1/3+i(5sqrt(2))/6 ,e= 1/3-i(5sqrt(2))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 e^{2} + 9 = 4 e

e = \frac{1}{3} + i \frac{5 2}{6}, e = \frac{1}{3} - i \frac{5 2}{6}

Solution steps

6 e^{2} + 9 = 4 e

Move

4 e

to the left side

6 e^{2} + 9 - 4 e = 0

Write in the standard form

a x^{2} + b x + c = 0

6 e^{2} - 4 e + 9 = 0

Solve with the quadratic formula

e_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 \cdot 9}{2 \cdot 6}

Simplify

(- 4)^{2} - 4 \cdot 6 \cdot 9 : 102 i

e_{1, 2} = \frac{- ( - 4 ) \pm 10 2 i}{2 \cdot 6}

Separate the solutions

e_{1} = \frac{- ( - 4 ) + 10 2 i}{2 \cdot 6}, e_{2} = \frac{- ( - 4 ) - 10 2 i}{2 \cdot 6}

e = \frac{- ( - 4 ) + 10 2 i}{2 \cdot 6} : \frac{1}{3} + i \frac{5 2}{6}

e = \frac{- ( - 4 ) - 10 2 i}{2 \cdot 6} : \frac{1}{3} - i \frac{5 2}{6}

The solutions to the quadratic equation are:

e = \frac{1}{3} + i \frac{5 2}{6}, e = \frac{1}{3} - i \frac{5 2}{6}

(k - 1) x^{2} + 2 (k - 2) x + (k - 1) = 0

(4 x - 1)^{2} - 4 (4 x - 1) + 4 = 0

2 x^{2} = 10 x + 5

(x^{2} + x - 6) = 0

3 x^{2} - x + 12 = 0

What are the solutions to the equation 6e^2+9=4e ?
The solutions to the equation 6e^2+9=4e are e= 1/3+i(5sqrt(2))/6 ,e= 1/3-i(5sqrt(2))/6
Find the zeros of 6e^2+9=4e
The zeros of 6e^2+9=4e are e= 1/3+i(5sqrt(2))/6 ,e= 1/3-i(5sqrt(2))/6