What are the solutions to the equation n^2-7n=-10 ?

The solutions to the equation n^2-7n=-10 are n=5,n=2

Find the zeros of n^2-7n=-10

The zeros of n^2-7n=-10 are n=5,n=2

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n^{2} - 7 n = - 10

n = 5, n = 2

Solution steps

n^{2} - 7 n = - 10

Move

10

to the left side

n^{2} - 7 n + 10 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

n_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, n_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

n = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

n = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

n = 5, n = 2

x^{2} + 5 x - 9 = 5

- x^{2} = 8

- x^{2} = 3

p, 2 (p - q)^{2} - (p - q) - 1 = 0

m^{2} + m - 56 = 0

What are the solutions to the equation n^2-7n=-10 ?
The solutions to the equation n^2-7n=-10 are n=5,n=2
Find the zeros of n^2-7n=-10
The zeros of n^2-7n=-10 are n=5,n=2