What are the solutions to the equation completesquare x^2+8x+13=0 ?

The solutions to the equation completesquare x^2+8x+13=0 are x=sqrt(3)-4,x=-sqrt(3)-4

Find the zeros of completesquare x^2+8x+13=0

The zeros of completesquare x^2+8x+13=0 are x=sqrt(3)-4,x=-sqrt(3)-4

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x^{2} + 8 x + 13 = 0

x = 3 - 4, x = - 3 - 4

Decimal Notation

x = - 2.26794 \dots, x = - 5.73205 \dots

Solution steps

x^{2} + 8 x + 13 = 0

Move

13

to the right side

x^{2} + 8 x = - 13

Rewrite in the form

(x + a)^{2} = b

(x + 4)^{2} = 3

For

the solutions are

f (x) = a, - a

Solve

x + 4 = 3 : x = 3 - 4

Solve

x + 4 = - 3 : x = - 3 - 4

The solutions to the quadratic equation are:

x = 3 - 4, x = - 3 - 4

x^{2} + 3 x + 54 = 0

3 x^{2} - x + 10 = 8

2 x^{2} - 20 = 12

x^{2} + 8 x + 12 = 0

2 x = (lo g_{10} (3)) x^{2}

What are the solutions to the equation completesquare x^2+8x+13=0 ?
The solutions to the equation completesquare x^2+8x+13=0 are x=sqrt(3)-4,x=-sqrt(3)-4
Find the zeros of completesquare x^2+8x+13=0
The zeros of completesquare x^2+8x+13=0 are x=sqrt(3)-4,x=-sqrt(3)-4