What are the solutions to the equation 1/16 x^2+x+4=0 ?

The solutions to the equation 1/16 x^2+x+4=0 are x=-8

Find the zeros of 1/16 x^2+x+4=0

The zeros of 1/16 x^2+x+4=0 are x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{16} x^{2} + x + 4 = 0

x = - 8

Solution steps

\frac{1}{16} x^{2} + x + 4 = 0

Multiply both sides by

16

x^{2} + 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 1}

x = \frac{- 16}{2 \cdot 1}

\frac{- 16}{2 \cdot 1} = - 8

x = - 8

The solution to the quadratic equation is:

x = - 8

x^{2} + 28 x

1 + 4 + 7 + 10 (3 n - 2) = \frac{n ( 3 n - 1 )}{2}

2 x (1 + x) = 4

4 k (k + 3) = - 15

s^{2} + 5 s + 9 = 0

What are the solutions to the equation 1/16 x^2+x+4=0 ?
The solutions to the equation 1/16 x^2+x+4=0 are x=-8
Find the zeros of 1/16 x^2+x+4=0
The zeros of 1/16 x^2+x+4=0 are x=-8