What are the solutions to the equation 1/3 (x-4)^2=-3 ?

The solutions to the equation 1/3 (x-4)^2=-3 are x=3i+4,x=-3i+4

Find the zeros of 1/3 (x-4)^2=-3

The zeros of 1/3 (x-4)^2=-3 are x=3i+4,x=-3i+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{3} (x - 4)^{2} = - 3

x = 3 i + 4, x = - 3 i + 4

Solution steps

\frac{1}{3} (x - 4)^{2} = - 3

Multiply both sides by

3

(x - 4)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 9 : x = 3 i + 4

Solve

x - 4 = - - 9 : x = - 3 i + 4

The solutions to the quadratic equation are:

x = 3 i + 4, x = - 3 i + 4

2 x^{2} - 10 x + 20 = 9

x^{2} + 4 x = 16

(x + 5)^{2} + (x)^{2} = 1 9^{2}

y, 4 x^{2} - 4 x y + 1 - y^{2} = 0

x^{2} - 5 = 95

What are the solutions to the equation 1/3 (x-4)^2=-3 ?
The solutions to the equation 1/3 (x-4)^2=-3 are x=3i+4,x=-3i+4
Find the zeros of 1/3 (x-4)^2=-3
The zeros of 1/3 (x-4)^2=-3 are x=3i+4,x=-3i+4