What are the solutions to the equation 5x^2+21x+18=0 ?

The solutions to the equation 5x^2+21x+18=0 are x=-6/5 ,x=-3

Find the zeros of 5x^2+21x+18=0

The zeros of 5x^2+21x+18=0 are x=-6/5 ,x=-3

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5 x^{2} + 21 x + 18 = 0

x = - \frac{6}{5}, x = - 3

Decimal Notation

x = - 1.2, x = - 3

Solution steps

5 x^{2} + 21 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 5 \cdot 18}{2 \cdot 5}

2 1^{2} - 4 \cdot 5 \cdot 18 = 9

x_{1, 2} = \frac{- 21 \pm 9}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 21 + 9}{2 \cdot 5}, x_{2} = \frac{- 21 - 9}{2 \cdot 5}

x = \frac{- 21 + 9}{2 \cdot 5} : - \frac{6}{5}

x = \frac{- 21 - 9}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = - \frac{6}{5}, x = - 3

6 x^{2} - 12 x - 38 = 10

x^{2} = 14 x - 49

3 (x - 4)^{2} = 0

s^{2} + 5 s + 7 = 0

6 x^{2} - 54 x + 108 = 0

What are the solutions to the equation 5x^2+21x+18=0 ?
The solutions to the equation 5x^2+21x+18=0 are x=-6/5 ,x=-3
Find the zeros of 5x^2+21x+18=0
The zeros of 5x^2+21x+18=0 are x=-6/5 ,x=-3