What are the solutions to the equation -x^2+11x-24=0 ?

The solutions to the equation -x^2+11x-24=0 are x=3,x=8

Find the zeros of -x^2+11x-24=0

The zeros of -x^2+11x-24=0 are x=3,x=8

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- x^{2} + 11 x - 24 = 0

x = 3, x = 8

Solution steps

- x^{2} + 11 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 1 ) ( - 24 )}{2 ( - 1 )}

1 1^{2} - 4 (- 1) (- 24) = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 ( - 1 )}, x_{2} = \frac{- 11 - 5}{2 ( - 1 )}

x = \frac{- 11 + 5}{2 ( - 1 )} : 3

x = \frac{- 11 - 5}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 3, x = 8

- \frac{550 x ^{2}}{2} + \frac{2000 ( x - 4 ) ^{2}}{2} + 3200 = 0

- 7 a^{5} n^{2} = 2

x (x - 15) = 100

x, x^{2} + 4 x y + 4 y^{2} - 3 x + 4 y - 10 = 0

x (x + 1) - (4 - x) (x + 1) = 6 (4 - x)

What are the solutions to the equation -x^2+11x-24=0 ?
The solutions to the equation -x^2+11x-24=0 are x=3,x=8
Find the zeros of -x^2+11x-24=0
The zeros of -x^2+11x-24=0 are x=3,x=8