What are the solutions to the equation -2x^2-5x+19=0 ?

The solutions to the equation -2x^2-5x+19=0 are x=-(5+sqrt(177))/4 ,x=(sqrt(177)-5)/4

Find the zeros of -2x^2-5x+19=0

The zeros of -2x^2-5x+19=0 are x=-(5+sqrt(177))/4 ,x=(sqrt(177)-5)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 5 x + 19 = 0

x = - \frac{5 + 177}{4}, x = \frac{177 - 5}{4}

Decimal Notation

x = - 4.57603 \dots, x = 2.07603 \dots

Solution steps

- 2 x^{2} - 5 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) \cdot 19}{2 ( - 2 )}

(- 5)^{2} - 4 (- 2) \cdot 19 = 177

x_{1, 2} = \frac{- ( - 5 ) \pm 177}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 177}{2 ( - 2 )}, x_{2} = \frac{- ( - 5 ) - 177}{2 ( - 2 )}

x = \frac{- ( - 5 ) + 177}{2 ( - 2 )} : - \frac{5 + 177}{4}

x = \frac{- ( - 5 ) - 177}{2 ( - 2 )} : \frac{177 - 5}{4}

The solutions to the quadratic equation are:

x = - \frac{5 + 177}{4}, x = \frac{177 - 5}{4}

0.02 t^{2} - 1.88 t + 43.56 = 0

(x + 2)^{2} - 3 (x + 2) - 54 = 0

x, y = (x + 2)^{2}

k^{2} = 12 k + 6

a, 4 y^{3} = a^{2} (x + 3 y)

What are the solutions to the equation -2x^2-5x+19=0 ?
The solutions to the equation -2x^2-5x+19=0 are x=-(5+sqrt(177))/4 ,x=(sqrt(177)-5)/4
Find the zeros of -2x^2-5x+19=0
The zeros of -2x^2-5x+19=0 are x=-(5+sqrt(177))/4 ,x=(sqrt(177)-5)/4