What are the solutions to the equation (x/3)^2=(4/6)^2+(6/2)^2 ?

The solutions to the equation (x/3)^2=(4/6)^2+(6/2)^2 are x=sqrt(85),x=-sqrt(85)

Find the zeros of (x/3)^2=(4/6)^2+(6/2)^2

The zeros of (x/3)^2=(4/6)^2+(6/2)^2 are x=sqrt(85),x=-sqrt(85)

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(\frac{x}{3})^{2} = (\frac{4}{6})^{2} + (\frac{6}{2})^{2}

x = 85, x = - 85

Decimal Notation

x = 9.21954 \dots, x = - 9.21954 \dots

Solution steps

(\frac{x}{3})^{2} = (\frac{4}{6})^{2} + (\frac{6}{2})^{2}

Simplify

(\frac{4}{6})^{2} + (\frac{6}{2})^{2} : \frac{85}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{x}{3} = \frac{85}{9} : x = 85

Solve

\frac{x}{3} = - \frac{85}{9} : x = - 85

The solutions to the quadratic equation are:

x = 85, x = - 85

x^{2} + (1 + 2 j) \cdot x = (\frac{3}{4} + j)

q^{2} + 8 q + 16 = - 3 q^{2} + 6 q + 436

x^{2} - x = 3 (x + 7)

(m + 1) x^{2} + (2 m + 3) x - 14 = 0

x^{2} = 3 (x - 1)

What are the solutions to the equation (x/3)^2=(4/6)^2+(6/2)^2 ?
The solutions to the equation (x/3)^2=(4/6)^2+(6/2)^2 are x=sqrt(85),x=-sqrt(85)
Find the zeros of (x/3)^2=(4/6)^2+(6/2)^2
The zeros of (x/3)^2=(4/6)^2+(6/2)^2 are x=sqrt(85),x=-sqrt(85)