What are the solutions to the equation 7-4t-0.5t^2=0 ?

The solutions to the equation 7-4t-0.5t^2=0 are t=-4-sqrt(30),t=sqrt(30)-4

Find the zeros of 7-4t-0.5t^2=0

The zeros of 7-4t-0.5t^2=0 are t=-4-sqrt(30),t=sqrt(30)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 - 4 t - 0.5 t^{2} = 0

t = - 4 - 30, t = 30 - 4

Decimal Notation

t = - 9.47722 \dots, t = 1.47722 \dots

Solution steps

7 - 4 t - 0.5 t^{2} = 0

Multiply both sides by

10

70 - 40 t - 5 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 t^{2} - 40 t + 70 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 5 ) \cdot 70}{2 ( - 5 )}

(- 40)^{2} - 4 (- 5) \cdot 70 = 1030

t_{1, 2} = \frac{- ( - 40 ) \pm 10 30}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- ( - 40 ) + 10 30}{2 ( - 5 )}, t_{2} = \frac{- ( - 40 ) - 10 30}{2 ( - 5 )}

t = \frac{- ( - 40 ) + 10 30}{2 ( - 5 )} : - 4 - 30

t = \frac{- ( - 40 ) - 10 30}{2 ( - 5 )} : 30 - 4

The solutions to the quadratic equation are:

t = - 4 - 30, t = 30 - 4

2 x^{2} + 7 x - 8 = 0

\frac{1 4 ^{2}}{2 0 ^{2}} + \frac{y ^{2}}{1 5 ^{2}} = 1

(3 - x) (- 3 - x) + 9 = 0

x^{2} = - 2 x - 14

- 6 x^{2} - 10 x = 0

What are the solutions to the equation 7-4t-0.5t^2=0 ?
The solutions to the equation 7-4t-0.5t^2=0 are t=-4-sqrt(30),t=sqrt(30)-4
Find the zeros of 7-4t-0.5t^2=0
The zeros of 7-4t-0.5t^2=0 are t=-4-sqrt(30),t=sqrt(30)-4