What are the solutions to the equation x^2-12x+13=0 ?

The solutions to the equation x^2-12x+13=0 are x=6+sqrt(23),x=6-sqrt(23)

Find the zeros of x^2-12x+13=0

The zeros of x^2-12x+13=0 are x=6+sqrt(23),x=6-sqrt(23)

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x^{2} - 12 x + 13 = 0

x = 6 + 23, x = 6 - 23

Decimal Notation

x = 10.79583 \dots, x = 1.20416 \dots

Solution steps

x^{2} - 12 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 13 = 223

x_{1, 2} = \frac{- ( - 12 ) \pm 2 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 23}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 23}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 23}{2 \cdot 1} : 6 + 23

x = \frac{- ( - 12 ) - 2 23}{2 \cdot 1} : 6 - 23

The solutions to the quadratic equation are:

x = 6 + 23, x = 6 - 23

- 0.5 x^{2} + 40 x - 300 = 15000

2 x^{2} + b x + c = 0

x^{2} - 2 x - 4 = 0

6 (3 x - 1) (2 x - 1) - 12 x^{2} = 7 x (2 x - 1)

- x^{2} + 3 x + 4 = x + 1

What are the solutions to the equation x^2-12x+13=0 ?
The solutions to the equation x^2-12x+13=0 are x=6+sqrt(23),x=6-sqrt(23)
Find the zeros of x^2-12x+13=0
The zeros of x^2-12x+13=0 are x=6+sqrt(23),x=6-sqrt(23)