What are the solutions to the equation z^2=-2 ?

The solutions to the equation z^2=-2 are z=sqrt(2)i,z=-sqrt(2)i

Find the zeros of z^2=-2

The zeros of z^2=-2 are z=sqrt(2)i,z=-sqrt(2)i

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z^{2} = - 2

z = 2 i, z = - 2 i

Solution steps

z^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 2, z = - - 2

- 2 = 2 i

- - 2 = - 2 i

z = 2 i, z = - 2 i

x^{2} + 4 x - 32 = 0

z^{2} = 2 z

\frac{1}{2} x^{2} - 4 x + 4 = 0

n^{2} + n - 3 = 0

z^{2} + 6 z + 25 = 0

What are the solutions to the equation z^2=-2 ?
The solutions to the equation z^2=-2 are z=sqrt(2)i,z=-sqrt(2)i
Find the zeros of z^2=-2
The zeros of z^2=-2 are z=sqrt(2)i,z=-sqrt(2)i