What are the solutions to the equation 9(w-4)^2+1=0 ?

The solutions to the equation 9(w-4)^2+1=0 are w=4+i 1/3 ,w=4-i 1/3

Find the zeros of 9(w-4)^2+1=0

The zeros of 9(w-4)^2+1=0 are w=4+i 1/3 ,w=4-i 1/3

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9 (w - 4)^{2} + 1 = 0

w = 4 + i \frac{1}{3}, w = 4 - i \frac{1}{3}

Solution steps

9 (w - 4)^{2} + 1 = 0

Move

1

to the right side

9 (w - 4)^{2} = - 1

Divide both sides by

9

(w - 4)^{2} = - \frac{1}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

w - 4 = - \frac{1}{9} : w = 4 + i \frac{1}{3}

Solve

w - 4 = - - \frac{1}{9} : w = 4 - i \frac{1}{3}

The solutions to the quadratic equation are:

w = 4 + i \frac{1}{3}, w = 4 - i \frac{1}{3}

(x + 4) (x - 4) = 5 x (x + 4)

\frac{1}{4} x^{2} - 1 = 0

a^{2} + 2 a - 48 = 0

s^{2} + 2 s + 16 = 0

- 2 (x + 6)^{2} = 20

What are the solutions to the equation 9(w-4)^2+1=0 ?
The solutions to the equation 9(w-4)^2+1=0 are w=4+i 1/3 ,w=4-i 1/3
Find the zeros of 9(w-4)^2+1=0
The zeros of 9(w-4)^2+1=0 are w=4+i 1/3 ,w=4-i 1/3