What are the solutions to the equation factor 15b^2+4b-4=0 ?

The solutions to the equation factor 15b^2+4b-4=0 are b= 2/5 ,b=-2/3

Find the zeros of factor 15b^2+4b-4=0

The zeros of factor 15b^2+4b-4=0 are b= 2/5 ,b=-2/3

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15 b^{2} + 4 b - 4 = 0

b = \frac{2}{5}, b = - \frac{2}{3}

Decimal Notation

b = 0.4, b = - 0.66666 \dots

Solution steps

15 b^{2} + 4 b - 4 = 0

Factor

15 b^{2} + 4 b - 4 : (5 b - 2) (3 b + 2)

(5 b - 2) (3 b + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 b - 2 = 0 or 3 b + 2 = 0

Solve

5 b - 2 = 0 : b = \frac{2}{5}

Solve

3 b + 2 = 0 : b = - \frac{2}{3}

The solutions to the quadratic equation are:

b = \frac{2}{5}, b = - \frac{2}{3}

8^{2} + 1 7^{2} = x^{2}

2 5^{2} = 2 4^{2} + a^{2}

x, (x^{2} + 9) y^{3} = - x y

(x + 2) (x - 2) - 5 = 0

8 k + 72 k^{2} = 0

What are the solutions to the equation factor 15b^2+4b-4=0 ?
The solutions to the equation factor 15b^2+4b-4=0 are b= 2/5 ,b=-2/3
Find the zeros of factor 15b^2+4b-4=0
The zeros of factor 15b^2+4b-4=0 are b= 2/5 ,b=-2/3