What is (3+8i)+(7-2i)-(6-5i) ?

The solution to (3+8i)+(7-2i)-(6-5i) is 4+11i

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simplify (3+8i)+(7-2i)-(6-5i)

simplify

(3 + 8 i) + (7 - 2 i) - (6 - 5 i)

4 + 11 i

Solution steps

(3 + 8 i) + (7 - 2 i) - (6 - 5 i)

Simplify

(3 + 8 i) + (7 - 2 i) - (6 - 5 i) : 3 + 8 i + 7 - 2 i - (6 - 5 i)

= 3 + 8 i + 7 - 2 i - (6 - 5 i)

Group like terms

= 8 i - 2 i - (6 - 5 i) + 3 + 7

Add similar elements:

8 i - 2 i = 6 i

= 6 i - (6 - 5 i) + 3 + 7

Add the numbers:

3 + 7 = 10

= 6 i - (6 - 5 i) + 10

Remove parentheses:

- (a + bi) = - a - bi

= 6 i + - 6 - (- 5) i + 10

Group like terms

= 6 i - (- 5) i - 6 + 10

Add similar elements:

6 i - (- 5) i = 11 i

= 11 i - 6 + 10

Add the numbers:

- 6 + 10 = 4

= 11 i + 4

Rewrite in standard complex form:

4 + 11 i

= 4 + 11 i

- 18 x^{2} - 18 x + 30

4^{\frac{7}{2}}

0.3 (4 + x) = 4.5

2 x^{4} - 3 x^{2} - 14

- 2 < 8 - 2 x \leq - 1