What are the solutions to the equation 3x^2-x-173=11x+7 ?

The solutions to the equation 3x^2-x-173=11x+7 are x=10,x=-6

Find the zeros of 3x^2-x-173=11x+7

The zeros of 3x^2-x-173=11x+7 are x=10,x=-6

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3 x^{2} - x - 173 = 11 x + 7

x = 10, x = - 6

Solution steps

3 x^{2} - x - 173 = 11 x + 7

Move

7

to the left side

3 x^{2} - x - 180 = 11 x

Move

11 x

to the left side

3 x^{2} - 12 x - 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 180 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 180) = 48

x_{1, 2} = \frac{- ( - 12 ) \pm 48}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 48}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 48}{2 \cdot 3}

x = \frac{- ( - 12 ) + 48}{2 \cdot 3} : 10

x = \frac{- ( - 12 ) - 48}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

x = 10, x = - 6

x^{2} + 4 x - 27 = 0

0 = (5 x^{2} - 3)

5 - 2 x^{2} = 0

6 x^{2} + 15 x + 3 = 2 x^{2}

s^{2} + 1.16 s + 1.042

What are the solutions to the equation 3x^2-x-173=11x+7 ?
The solutions to the equation 3x^2-x-173=11x+7 are x=10,x=-6
Find the zeros of 3x^2-x-173=11x+7
The zeros of 3x^2-x-173=11x+7 are x=10,x=-6