What are the solutions to the equation 2n^2-n^2-5n=24 ?

The solutions to the equation 2n^2-n^2-5n=24 are n=8,n=-3

Find the zeros of 2n^2-n^2-5n=24

The zeros of 2n^2-n^2-5n=24 are n=8,n=-3

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2 n^{2} - n^{2} - 5 n = 24

n = 8, n = - 3

Solution steps

2 n^{2} - n^{2} - 5 n = 24

Refine

n^{2} - 5 n = 24

Move

24

to the left side

n^{2} - 5 n - 24 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 24) = 11

n_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 1}, n_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 1}

n = \frac{- ( - 5 ) + 11}{2 \cdot 1} : 8

n = \frac{- ( - 5 ) - 11}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

n = 8, n = - 3

x^{2} + 13.6 x = 53.76

10 x^{2} + 8 = 108

12 x^{2} + 30 x - 18 = 0

x^{2} - x - \frac{11}{4} = 0

2 (x - 1)^{2} = 72

What are the solutions to the equation 2n^2-n^2-5n=24 ?
The solutions to the equation 2n^2-n^2-5n=24 are n=8,n=-3
Find the zeros of 2n^2-n^2-5n=24
The zeros of 2n^2-n^2-5n=24 are n=8,n=-3