What are the solutions to the equation 3(x-4)^2+15=-9 ?

The solutions to the equation 3(x-4)^2+15=-9 are x=2sqrt(2)i+4,x=-2sqrt(2)i+4

Find the zeros of 3(x-4)^2+15=-9

The zeros of 3(x-4)^2+15=-9 are x=2sqrt(2)i+4,x=-2sqrt(2)i+4

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3 (x - 4)^{2} + 15 = - 9

x = 22 i + 4, x = - 22 i + 4

Solution steps

3 (x - 4)^{2} + 15 = - 9

Move

15

to the right side

3 (x - 4)^{2} = - 24

Divide both sides by

3

(x - 4)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 8 : x = 22 i + 4

Solve

x - 4 = - - 8 : x = - 22 i + 4

The solutions to the quadratic equation are:

x = 22 i + 4, x = - 22 i + 4

9 x^{2} + 12 x = - 6

x, 3 x^{2} + x + 1 = 0

2 x^{2} + 9 x - 11 = 0

x^{2} = \frac{8}{3}

(2 x + 3) (2 x - 3) + (x + 3)^{2} = 16 x

What are the solutions to the equation 3(x-4)^2+15=-9 ?
The solutions to the equation 3(x-4)^2+15=-9 are x=2sqrt(2)i+4,x=-2sqrt(2)i+4
Find the zeros of 3(x-4)^2+15=-9
The zeros of 3(x-4)^2+15=-9 are x=2sqrt(2)i+4,x=-2sqrt(2)i+4