What are the solutions to the equation v^2-6v+8=0 ?

The solutions to the equation v^2-6v+8=0 are v=4,v=2

Find the zeros of v^2-6v+8=0

The zeros of v^2-6v+8=0 are v=4,v=2

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v^{2} - 6 v + 8 = 0

v = 4, v = 2

Solution steps

v^{2} - 6 v + 8 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

v_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, v_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

v = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

v = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

v = 4, v = 2

2 x^{2} + 8 x = 7

q (q - 3) - 4 = 0

128 = - 16 t^{2} + 32 t + 128

x^{2} + x - 2

4 x^{2} + 16 x - 53 = 5

What are the solutions to the equation v^2-6v+8=0 ?
The solutions to the equation v^2-6v+8=0 are v=4,v=2
Find the zeros of v^2-6v+8=0
The zeros of v^2-6v+8=0 are v=4,v=2