What are the solutions to the equation x^2+4x-23=0 ?

The solutions to the equation x^2+4x-23=0 are x=-2+3sqrt(3),x=-2-3sqrt(3)

Find the zeros of x^2+4x-23=0

The zeros of x^2+4x-23=0 are x=-2+3sqrt(3),x=-2-3sqrt(3)

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x^{2} + 4 x - 23 = 0

x = - 2 + 33, x = - 2 - 33

Decimal Notation

x = 3.19615 \dots, x = - 7.19615 \dots

Solution steps

x^{2} + 4 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 23) = 63

x_{1, 2} = \frac{- 4 \pm 6 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6 3}{2 \cdot 1}, x_{2} = \frac{- 4 - 6 3}{2 \cdot 1}

x = \frac{- 4 + 6 3}{2 \cdot 1} : - 2 + 33

x = \frac{- 4 - 6 3}{2 \cdot 1} : - 2 - 33

The solutions to the quadratic equation are:

x = - 2 + 33, x = - 2 - 33

3 x^{2} - 19 x - 40 = 0

\frac{9 x ^{2} - 0}{9} - \frac{4 x - 0}{4} + 6 = 0

30.7 \cdot x^{2} + 57 = A x (x + 33.3) + B \cdot (x + 33.3) + C \cdot x^{2}

3 (\frac{4}{5}) x^{2} + 6 x - 5 = 0

x^{2} + 2 x + c = 0

What are the solutions to the equation x^2+4x-23=0 ?
The solutions to the equation x^2+4x-23=0 are x=-2+3sqrt(3),x=-2-3sqrt(3)
Find the zeros of x^2+4x-23=0
The zeros of x^2+4x-23=0 are x=-2+3sqrt(3),x=-2-3sqrt(3)