What are the solutions to the equation x^2+4x-22=0 ?

The solutions to the equation x^2+4x-22=0 are x=-2+sqrt(26),x=-2-sqrt(26)

Find the zeros of x^2+4x-22=0

The zeros of x^2+4x-22=0 are x=-2+sqrt(26),x=-2-sqrt(26)

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x^{2} + 4 x - 22 = 0

x = - 2 + 26, x = - 2 - 26

Decimal Notation

x = 3.09901 \dots, x = - 7.09901 \dots

Solution steps

x^{2} + 4 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 22) = 226

x_{1, 2} = \frac{- 4 \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 26}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 26}{2 \cdot 1}

x = \frac{- 4 + 2 26}{2 \cdot 1} : - 2 + 26

x = \frac{- 4 - 2 26}{2 \cdot 1} : - 2 - 26

The solutions to the quadratic equation are:

x = - 2 + 26, x = - 2 - 26

x^{2} - 12 x - 1725 = 0

2 x^{2} + 5 x = - 4

2 x^{2} + 5 x = - 2

x^{2} - 4 = 0

x, 6 x^{2} y + 3 x = y^{4} - 9 x y

What are the solutions to the equation x^2+4x-22=0 ?
The solutions to the equation x^2+4x-22=0 are x=-2+sqrt(26),x=-2-sqrt(26)
Find the zeros of x^2+4x-22=0
The zeros of x^2+4x-22=0 are x=-2+sqrt(26),x=-2-sqrt(26)