What are the solutions to the equation v^2=-28 ?

The solutions to the equation v^2=-28 are v=2sqrt(7)i,v=-2sqrt(7)i

Find the zeros of v^2=-28

The zeros of v^2=-28 are v=2sqrt(7)i,v=-2sqrt(7)i

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v^{2} = - 28

v = 27 i, v = - 27 i

Solution steps

v^{2} = - 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = - 28, v = - - 28

- 28 = 27 i

- - 28 = - 27 i

v = 27 i, v = - 27 i

- 2 x^{2} + 5 x + 2 = 0

11 x + 18 = x^{2}

(2 x - \frac{13}{4})^{2} = \frac{121}{16}

x^{2} + 30 = 25

x, 29 x^{2} - 24 x y + 36 y^{2} + 82 x - 96 y - 91 = 0

What are the solutions to the equation v^2=-28 ?
The solutions to the equation v^2=-28 are v=2sqrt(7)i,v=-2sqrt(7)i
Find the zeros of v^2=-28
The zeros of v^2=-28 are v=2sqrt(7)i,v=-2sqrt(7)i