What are the solutions to the equation 1/4 x^2+4/3 x-7=0 ?

The solutions to the equation 1/4 x^2+4/3 x-7=0 are x=(2(sqrt(79)-4))/3 ,x=-(2(4+sqrt(79)))/3

Find the zeros of 1/4 x^2+4/3 x-7=0

The zeros of 1/4 x^2+4/3 x-7=0 are x=(2(sqrt(79)-4))/3 ,x=-(2(4+sqrt(79)))/3

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\frac{1}{4} x^{2} + \frac{4}{3} x - 7 = 0

x = \frac{2 ( 79 - 4 )}{3}, x = - \frac{2 ( 4 + 79 )}{3}

Decimal Notation

x = 3.25879 \dots, x = - 8.59212 \dots

Solution steps

\frac{1}{4} x^{2} + \frac{4}{3} x - 7 = 0

Find Least Common Multiplier of

4, 3 : 12

Multiply by LCM=

12

\frac{1}{4} x^{2} \cdot 12 + \frac{4}{3} x \cdot 12 - 7 \cdot 12 = 0 \cdot 12

Simplify

3 x^{2} + 16 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 ( - 84 )}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 (- 84) = 479

x_{1, 2} = \frac{- 16 \pm 4 79}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 16 + 4 79}{2 \cdot 3}, x_{2} = \frac{- 16 - 4 79}{2 \cdot 3}

x = \frac{- 16 + 4 79}{2 \cdot 3} : \frac{2 ( 79 - 4 )}{3}

x = \frac{- 16 - 4 79}{2 \cdot 3} : - \frac{2 ( 4 + 79 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 79 - 4 )}{3}, x = - \frac{2 ( 4 + 79 )}{3}

n^{2} - 16 n + 67 = 4

2 x^{2} - x + 3 = x + 9

x^{2} - x - 1 = - 1

x, x^{2} + 2 x + 4 = 0

\frac{1}{2} x^{2} - x + 1 = 0

What are the solutions to the equation 1/4 x^2+4/3 x-7=0 ?
The solutions to the equation 1/4 x^2+4/3 x-7=0 are x=(2(sqrt(79)-4))/3 ,x=-(2(4+sqrt(79)))/3
Find the zeros of 1/4 x^2+4/3 x-7=0
The zeros of 1/4 x^2+4/3 x-7=0 are x=(2(sqrt(79)-4))/3 ,x=-(2(4+sqrt(79)))/3