What are the solutions to the equation x^2-x-11=1 ?

The solutions to the equation x^2-x-11=1 are x=4,x=-3

Find the zeros of x^2-x-11=1

The zeros of x^2-x-11=1 are x=4,x=-3

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x^{2} - x - 11 = 1

x = 4, x = - 3

Solution steps

x^{2} - x - 11 = 1

Move

1

to the left side

x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

x = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

x = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 4, x = - 3

y, \frac{3 y ^{2}}{m} + m = \frac{7 y}{2}

4 x^{2} - 42 x = 7 x - 12

5 x^{2} - 14 x - 3

- 4 x^{2} + x = 0

x^{2} = 3 x + 8

What are the solutions to the equation x^2-x-11=1 ?
The solutions to the equation x^2-x-11=1 are x=4,x=-3
Find the zeros of x^2-x-11=1
The zeros of x^2-x-11=1 are x=4,x=-3