What are the solutions to the equation x^2-8x=-20 ?

The solutions to the equation x^2-8x=-20 are x=4+2i,x=4-2i

Find the zeros of x^2-8x=-20

The zeros of x^2-8x=-20 are x=4+2i,x=4-2i

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x^{2} - 8 x = - 20

x = 4 + 2 i, x = 4 - 2 i

Solution steps

x^{2} - 8 x = - 20

Move

20

to the left side

x^{2} - 8 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 20 : 4 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4 i}{2 \cdot 1} : 4 + 2 i

x = \frac{- ( - 8 ) - 4 i}{2 \cdot 1} : 4 - 2 i

The solutions to the quadratic equation are:

x = 4 + 2 i, x = 4 - 2 i

x^{2} + x + 9 = 0

16 - x^{2} = - 20

3 x^{2} + 2 = 4 x

r, s = 2 π r h + 2 π r^{2}

2 x - x^{2} - 1 = 0

What are the solutions to the equation x^2-8x=-20 ?
The solutions to the equation x^2-8x=-20 are x=4+2i,x=4-2i
Find the zeros of x^2-8x=-20
The zeros of x^2-8x=-20 are x=4+2i,x=4-2i