What are the solutions to the equation b(x)=-5x^2 ?

The solutions to the equation b(x)=-5x^2 are x=0,x=-b/5

Find the zeros of b(x)=-5x^2

The zeros of b(x)=-5x^2 are x=0,x=-b/5

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b (x) = - 5 x^{2}

x = 0, x = - \frac{b}{5}

Solution steps

b (x) = - 5 x^{2}

Move

5 x^{2}

to the left side

b x + 5 x^{2} = 0

Factor

b x + 5 x^{2} : x (b + 5 x)

x (b + 5 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or b + 5 x = 0

Solve

b + 5 x = 0 : x = - \frac{b}{5}

The solutions to the quadratic equation are:

x = 0, x = - \frac{b}{5}

4 = 3 x^{2} + 14 x + 4

500 (a^{2} - \frac{1}{81} a^{2}) = 0.8 \cdot 1000 \cdot 9.8 \cdot 0.05

x^{2} - 15 x + 54 = 0

16 x^{2} + 20 x = 0

x^{2} = - \frac{1}{4}

What are the solutions to the equation b(x)=-5x^2 ?
The solutions to the equation b(x)=-5x^2 are x=0,x=-b/5
Find the zeros of b(x)=-5x^2
The zeros of b(x)=-5x^2 are x=0,x=-b/5