What are the solutions to the equation p^2+2p+5=0 ?

The solutions to the equation p^2+2p+5=0 are p=-1+2i,p=-1-2i

Find the zeros of p^2+2p+5=0

The zeros of p^2+2p+5=0 are p=-1+2i,p=-1-2i

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p^{2} + 2 p + 5 = 0

p = - 1 + 2 i, p = - 1 - 2 i

Solution steps

p^{2} + 2 p + 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

p_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, p_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

p = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

p = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

p = - 1 + 2 i, p = - 1 - 2 i

- 8 x + 3 x^{2} = - 19

6 = \frac{3 t ^{2}}{2} - 3

x, x^{2} - 5 x = 0

x^{2} - 15 x = 100

y, 4 x^{3} - 2 y^{2} + 14 x = 0

What are the solutions to the equation p^2+2p+5=0 ?
The solutions to the equation p^2+2p+5=0 are p=-1+2i,p=-1-2i
Find the zeros of p^2+2p+5=0
The zeros of p^2+2p+5=0 are p=-1+2i,p=-1-2i