What are the solutions to the equation x^2-12x+40=13 ?

The solutions to the equation x^2-12x+40=13 are x=9,x=3

Find the zeros of x^2-12x+40=13

The zeros of x^2-12x+40=13 are x=9,x=3

Popular >

x^{2} - 12 x + 40 = 13

x = 9, x = 3

Solution steps

x^{2} - 12 x + 40 = 13

Move

13

to the left side

x^{2} - 12 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 27 = 6

x_{1, 2} = \frac{- ( - 12 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 6}{2 \cdot 1}

x = \frac{- ( - 12 ) + 6}{2 \cdot 1} : 9

x = \frac{- ( - 12 ) - 6}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 9, x = 3

x, f = 3 x^{2} + 4 y

2 x^{2} + x - 3 = 0

144 x^{2} - 864 x

X, F = 5 X^{2} - 2 Y^{2} + 3 Z^{3}

x, z = x^{2} + 2 y^{2} + x y + 3 x + 5 y

What are the solutions to the equation x^2-12x+40=13 ?
The solutions to the equation x^2-12x+40=13 are x=9,x=3
Find the zeros of x^2-12x+40=13
The zeros of x^2-12x+40=13 are x=9,x=3