What are the solutions to the equation -4x^2+36=4 ?

The solutions to the equation -4x^2+36=4 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of -4x^2+36=4

The zeros of -4x^2+36=4 are x=2sqrt(2),x=-2sqrt(2)

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- 4 x^{2} + 36 = 4

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

- 4 x^{2} + 36 = 4

Move

36

to the right side

- 4 x^{2} = - 32

Divide both sides by

- 4

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

4 x^{2} - 28 x + 49 = 25

- x^{2} - 8 x + 2 = 0

7 - 8 x - x^{2} = 0

25 x^{2} - 30 x + 18 = 9

3 x^{2} - 4 x - 11 = 4

What are the solutions to the equation -4x^2+36=4 ?
The solutions to the equation -4x^2+36=4 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of -4x^2+36=4
The zeros of -4x^2+36=4 are x=2sqrt(2),x=-2sqrt(2)