What are the solutions to the equation m^2-9m+8=0 ?

The solutions to the equation m^2-9m+8=0 are m=8,m=1

Find the zeros of m^2-9m+8=0

The zeros of m^2-9m+8=0 are m=8,m=1

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m^{2} - 9 m + 8 = 0

m = 8, m = 1

Solution steps

m^{2} - 9 m + 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

m_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, m_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

m = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

m = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

m = 8, m = 1

x^{2} = 4 x + 7

192 π = 2 π \cdot x \cdot 16 + 2 π \cdot x^{2}

3 x^{2} - 2 x = 40

2 x^{2} + 7 x + 6 = 0

5 x^{2} - 15 x + 1

What are the solutions to the equation m^2-9m+8=0 ?
The solutions to the equation m^2-9m+8=0 are m=8,m=1
Find the zeros of m^2-9m+8=0
The zeros of m^2-9m+8=0 are m=8,m=1