What are the solutions to the equation solvefor p,q=400-p^2 ?

The solutions to the equation solvefor p,q=400-p^2 are p=sqrt(-q+400),p=-sqrt(-q+400)

Find the zeros of solvefor p,q=400-p^2

The zeros of solvefor p,q=400-p^2 are p=sqrt(-q+400),p=-sqrt(-q+400)

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solve for

p, q = 400 - p^{2}

p = - q + 400, p = - - q + 400

Solution steps

q = 400 - p^{2}

Switch sides

400 - p^{2} = q

Move

400

to the right side

- p^{2} = q - 400

Divide both sides by

- 1

p^{2} = - q + 400

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - q + 400, p = - - q + 400

y = - \frac{1}{20} y^{2}

124 = 0.006 a^{2} - 0.02 a + 120

- x^{2} - 2 x + 7 = - 17

\frac{1}{4} x^{2} - x - 1 = \frac{1}{16} x^{2} - \frac{1}{4} x + \frac{5}{4}

X, 4 X^{2} + 9 y^{2} = 36

What are the solutions to the equation solvefor p,q=400-p^2 ?
The solutions to the equation solvefor p,q=400-p^2 are p=sqrt(-q+400),p=-sqrt(-q+400)
Find the zeros of solvefor p,q=400-p^2
The zeros of solvefor p,q=400-p^2 are p=sqrt(-q+400),p=-sqrt(-q+400)