What are the solutions to the equation solvefor x,z=x^2+y^2+2y+1 ?

The solutions to the equation solvefor x,z=x^2+y^2+2y+1 are x=sqrt(z-y^2-2y-1),x=-sqrt(z-y^2-2y-1)

Find the zeros of solvefor x,z=x^2+y^2+2y+1

The zeros of solvefor x,z=x^2+y^2+2y+1 are x=sqrt(z-y^2-2y-1),x=-sqrt(z-y^2-2y-1)

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solve for

x, z = x^{2} + y^{2} + 2 y + 1

x = z - y^{2} - 2 y - 1, x = - z - y^{2} - 2 y - 1

Solution steps

z = x^{2} + y^{2} + 2 y + 1

Switch sides

x^{2} + y^{2} + 2 y + 1 = z

Move

y^{2}

to the right side

x^{2} + 2 y + 1 = z - y^{2}

Move

2 y

to the right side

x^{2} + 1 = z - y^{2} - 2 y

Move

1

to the right side

x^{2} = z - y^{2} - 2 y - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = z - y^{2} - 2 y - 1, x = - z - y^{2} - 2 y - 1

4 x^{2} - 9 = 0

x, x^{2} + y^{2} + 2 x - 18 + 78 = 0

3 x^{2} = 4 x + 6

x, x^{2} + 3 = 0

12 x^{2} - 1 = 0

What are the solutions to the equation solvefor x,z=x^2+y^2+2y+1 ?
The solutions to the equation solvefor x,z=x^2+y^2+2y+1 are x=sqrt(z-y^2-2y-1),x=-sqrt(z-y^2-2y-1)
Find the zeros of solvefor x,z=x^2+y^2+2y+1
The zeros of solvefor x,z=x^2+y^2+2y+1 are x=sqrt(z-y^2-2y-1),x=-sqrt(z-y^2-2y-1)