What are the solutions to the equation -(x-2)^2+16=0 ?

The solutions to the equation -(x-2)^2+16=0 are x=6,x=-2

Find the zeros of -(x-2)^2+16=0

The zeros of -(x-2)^2+16=0 are x=6,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- (x - 2)^{2} + 16 = 0

x = 6, x = - 2

Solution steps

- (x - 2)^{2} + 16 = 0

Move

16

to the right side

- (x - 2)^{2} = - 16

Divide both sides by

- 1

(x - 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 16 : x = 6

Solve

x - 2 = - 16 : x = - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

6 - x^{2} + 8 x = 5 + 4 x

0 = 2.4 + 8.6 x - 4.9 \cdot x^{2}

(x + 49)^{2} = 24

0 = - 10 + n^{2}

x^{2} = 9 \cdot 4

What are the solutions to the equation -(x-2)^2+16=0 ?
The solutions to the equation -(x-2)^2+16=0 are x=6,x=-2
Find the zeros of -(x-2)^2+16=0
The zeros of -(x-2)^2+16=0 are x=6,x=-2