What is (3x-1)(10x+4)>= (6x-5)(5x-7) ?

The solution to (3x-1)(10x+4)>= (6x-5)(5x-7) is x>= 13/23

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(3x-1)(10x+4)>= (6x-5)(5x-7)

(3 x - 1) (10 x + 4) \geq (6 x - 5) (5 x - 7)

x \geq \frac{13}{23}

Interval Notation

[\frac{13}{23}, \infty)

Decimal Notation

x \geq 0.56521 \dots

Solution steps

(3 x - 1) (10 x + 4) \geq (6 x - 5) (5 x - 7)

Rewrite in standard form

23 x - 13 \geq 0

Move

13

to the right side

23 x \geq 13

Divide both sides by

23

x \geq \frac{13}{23}

- x^{2} - x + 42

7 (5 w - 3) = - 36 (2 - w)

10 m^{5} + 5 m^{4} - 25 m^{2}

(4)^{2}

\frac{2 ^{2}}{- 3}

What is (3x-1)(10x+4)>= (6x-5)(5x-7) ?
The solution to (3x-1)(10x+4)>= (6x-5)(5x-7) is x>= 13/23