What are the solutions to the equation b^2=3 ?

The solutions to the equation b^2=3 are b=sqrt(3),b=-sqrt(3)

Find the zeros of b^2=3

The zeros of b^2=3 are b=sqrt(3),b=-sqrt(3)

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b^{2} = 3

b = 3, b = - 3

Decimal Notation

b = 1.73205 \dots, b = - 1.73205 \dots

Solution steps

b^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 3, b = - 3

b^{2} = 8

2 w^{2} + 5 w - 42 = 0

x^{2} - 11 x + 30 = 12

9 x^{2} + 12 x + 10 = 0

q, p = \frac{1}{2} q^{2} + 20

What are the solutions to the equation b^2=3 ?
The solutions to the equation b^2=3 are b=sqrt(3),b=-sqrt(3)
Find the zeros of b^2=3
The zeros of b^2=3 are b=sqrt(3),b=-sqrt(3)