What are the solutions to the equation x^2-12x+56=0 ?

The solutions to the equation x^2-12x+56=0 are x=6+2sqrt(5)i,x=6-2sqrt(5)i

Find the zeros of x^2-12x+56=0

The zeros of x^2-12x+56=0 are x=6+2sqrt(5)i,x=6-2sqrt(5)i

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x^{2} - 12 x + 56 = 0

x = 6 + 25 i, x = 6 - 25 i

Solution steps

x^{2} - 12 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 56 : 45 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 5 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 5 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 5 i}{2 \cdot 1} : 6 + 25 i

x = \frac{- ( - 12 ) - 4 5 i}{2 \cdot 1} : 6 - 25 i

The solutions to the quadratic equation are:

x = 6 + 25 i, x = 6 - 25 i

x^{2} - 10 x - 3 = 5

x, x^{2} - 2 = 0

x^{2} + 2 x - 48 = 0

\frac{1}{2} x^{2} = \frac{x}{4} + 1

x, x y - x^{2} = 2 x

What are the solutions to the equation x^2-12x+56=0 ?
The solutions to the equation x^2-12x+56=0 are x=6+2sqrt(5)i,x=6-2sqrt(5)i
Find the zeros of x^2-12x+56=0
The zeros of x^2-12x+56=0 are x=6+2sqrt(5)i,x=6-2sqrt(5)i