What are the solutions to the equation factor 12x^2-x-6=0 ?

The solutions to the equation factor 12x^2-x-6=0 are x=-2/3 ,x= 3/4

Find the zeros of factor 12x^2-x-6=0

The zeros of factor 12x^2-x-6=0 are x=-2/3 ,x= 3/4

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12 x^{2} - x - 6 = 0

x = - \frac{2}{3}, x = \frac{3}{4}

Decimal Notation

x = - 0.66666 \dots, x = 0.75

Solution steps

12 x^{2} - x - 6 = 0

Factor

12 x^{2} - x - 6 : (3 x + 2) (4 x - 3)

(3 x + 2) (4 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or 4 x - 3 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

4 x - 3 = 0 : x = \frac{3}{4}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = \frac{3}{4}

x^{2} + 2 x - 323 = 0

x^{2} = 5 x + 4

1 + 2 x^{2} = 0

X^{2} + X - 1 = 0

(x + 4)^{2} = 8 x + 24

What are the solutions to the equation factor 12x^2-x-6=0 ?
The solutions to the equation factor 12x^2-x-6=0 are x=-2/3 ,x= 3/4
Find the zeros of factor 12x^2-x-6=0
The zeros of factor 12x^2-x-6=0 are x=-2/3 ,x= 3/4