What are the solutions to the equation (-2t-5)(8t-5)=0 ?

The solutions to the equation (-2t-5)(8t-5)=0 are t=-5/2 ,t= 5/8

Find the zeros of (-2t-5)(8t-5)=0

The zeros of (-2t-5)(8t-5)=0 are t=-5/2 ,t= 5/8

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(- 2 t - 5) (8 t - 5) = 0

t = - \frac{5}{2}, t = \frac{5}{8}

Decimal Notation

t = - 2.5, t = 0.625

Solution steps

(- 2 t - 5) (8 t - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 2 t - 5 = 0 or 8 t - 5 = 0

Solve

- 2 t - 5 = 0 : t = - \frac{5}{2}

Solve

8 t - 5 = 0 : t = \frac{5}{8}

The solutions to the quadratic equation are:

t = - \frac{5}{2}, t = \frac{5}{8}

x (x - 10) = 21

x^{2} + 2 = 11

2 x^{2} + 65 x - 200 = 0

3 x^{2} + 7 x - 28 = 0

x^{2} + 9 = 9

What are the solutions to the equation (-2t-5)(8t-5)=0 ?
The solutions to the equation (-2t-5)(8t-5)=0 are t=-5/2 ,t= 5/8
Find the zeros of (-2t-5)(8t-5)=0
The zeros of (-2t-5)(8t-5)=0 are t=-5/2 ,t= 5/8