What are the solutions to the equation -4x^2+5x=6 ?

The solutions to the equation -4x^2+5x=6 are x= 5/8-i(sqrt(71))/8 ,x= 5/8+i(sqrt(71))/8

Find the zeros of -4x^2+5x=6

The zeros of -4x^2+5x=6 are x= 5/8-i(sqrt(71))/8 ,x= 5/8+i(sqrt(71))/8

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- 4 x^{2} + 5 x = 6

x = \frac{5}{8} - i \frac{71}{8}, x = \frac{5}{8} + i \frac{71}{8}

Solution steps

- 4 x^{2} + 5 x = 6

Move

6

to the left side

- 4 x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 4 ) ( - 6 )}{2 ( - 4 )}

Simplify

5^{2} - 4 (- 4) (- 6) : 71 i

x_{1, 2} = \frac{- 5 \pm 71 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 5 + 71 i}{2 ( - 4 )}, x_{2} = \frac{- 5 - 71 i}{2 ( - 4 )}

x = \frac{- 5 + 71 i}{2 ( - 4 )} : \frac{5}{8} - i \frac{71}{8}

x = \frac{- 5 - 71 i}{2 ( - 4 )} : \frac{5}{8} + i \frac{71}{8}

The solutions to the quadratic equation are:

x = \frac{5}{8} - i \frac{71}{8}, x = \frac{5}{8} + i \frac{71}{8}

X^{2} + X - 6 = 0

m (m + 1) - 36 = 0

c (x) = 0.3 x^{2} + 1.2 x + 4

x, x^{2} - y x + y^{2} = 7

y, f = x^{2} - x^{3} y^{2}

What are the solutions to the equation -4x^2+5x=6 ?
The solutions to the equation -4x^2+5x=6 are x= 5/8-i(sqrt(71))/8 ,x= 5/8+i(sqrt(71))/8
Find the zeros of -4x^2+5x=6
The zeros of -4x^2+5x=6 are x= 5/8-i(sqrt(71))/8 ,x= 5/8+i(sqrt(71))/8