What are the solutions to the equation 2x=x^2-8x+16 ?

The solutions to the equation 2x=x^2-8x+16 are x=8,x=2

Find the zeros of 2x=x^2-8x+16

The zeros of 2x=x^2-8x+16 are x=8,x=2

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2 x = x^{2} - 8 x + 16

x = 8, x = 2

Solution steps

2 x = x^{2} - 8 x + 16

Switch sides

x^{2} - 8 x + 16 = 2 x

Move

2 x

to the left side

x^{2} - 10 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

x = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 8, x = 2

x^{2} + 5 = 5

16 - 2 x^{2} = 144

x^{2} + 5 = x

2 x^{2} = 14 x

2 x^{2} + 4 x + 1 = 0

What are the solutions to the equation 2x=x^2-8x+16 ?
The solutions to the equation 2x=x^2-8x+16 are x=8,x=2
Find the zeros of 2x=x^2-8x+16
The zeros of 2x=x^2-8x+16 are x=8,x=2