What are the solutions to the equation 3x^2-2x-20=13x-2 ?

The solutions to the equation 3x^2-2x-20=13x-2 are x=6,x=-1

Find the zeros of 3x^2-2x-20=13x-2

The zeros of 3x^2-2x-20=13x-2 are x=6,x=-1

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3 x^{2} - 2 x - 20 = 13 x - 2

x = 6, x = - 1

Solution steps

3 x^{2} - 2 x - 20 = 13 x - 2

Move

2

to the left side

3 x^{2} - 2 x - 18 = 13 x

Move

13 x

to the left side

3 x^{2} - 15 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

(- 15)^{2} - 4 \cdot 3 (- 18) = 21

x_{1, 2} = \frac{- ( - 15 ) \pm 21}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 21}{2 \cdot 3}, x_{2} = \frac{- ( - 15 ) - 21}{2 \cdot 3}

x = \frac{- ( - 15 ) + 21}{2 \cdot 3} : 6

x = \frac{- ( - 15 ) - 21}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

4 y^{2} - 13 = y^{2} + 14

s^{2} + 9 s + 7 = 0

x^{2} = - 9 x + 15

(a x + 5)^{2} = 16 x^{2} + b x + 25

4 x^{2} - 10 x - 36 = 0

What are the solutions to the equation 3x^2-2x-20=13x-2 ?
The solutions to the equation 3x^2-2x-20=13x-2 are x=6,x=-1
Find the zeros of 3x^2-2x-20=13x-2
The zeros of 3x^2-2x-20=13x-2 are x=6,x=-1