What are the solutions to the equation 2x^2-10x+6=0 ?

The solutions to the equation 2x^2-10x+6=0 are x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2

Find the zeros of 2x^2-10x+6=0

The zeros of 2x^2-10x+6=0 are x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2

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2 x^{2} - 10 x + 6 = 0

x = \frac{5 + 13}{2}, x = \frac{5 - 13}{2}

Decimal Notation

x = 4.30277 \dots, x = 0.69722 \dots

Solution steps

2 x^{2} - 10 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 6 = 213

x_{1, 2} = \frac{- ( - 10 ) \pm 2 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 13}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 13}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 13}{2 \cdot 2} : \frac{5 + 13}{2}

x = \frac{- ( - 10 ) - 2 13}{2 \cdot 2} : \frac{5 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 13}{2}, x = \frac{5 - 13}{2}

- 3 x^{2} - 60 x - 230.5 = 0

\frac{1}{3} x^{2} = - 15

x^{2} - 3 x + 20 = 0

4 - 3 x - x^{2} = (3 x - 2)^{2} - 1

x^{2} - 6 + 5 = 0

What are the solutions to the equation 2x^2-10x+6=0 ?
The solutions to the equation 2x^2-10x+6=0 are x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2
Find the zeros of 2x^2-10x+6=0
The zeros of 2x^2-10x+6=0 are x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2