What are the solutions to the equation 4a^2-13a+3=0 ?

The solutions to the equation 4a^2-13a+3=0 are a=3,a= 1/4

Find the zeros of 4a^2-13a+3=0

The zeros of 4a^2-13a+3=0 are a=3,a= 1/4

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4 a^{2} - 13 a + 3 = 0

a = 3, a = \frac{1}{4}

Decimal Notation

a = 3, a = 0.25

Solution steps

4 a^{2} - 13 a + 3 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 13)^{2} - 4 \cdot 4 \cdot 3 = 11

a_{1, 2} = \frac{- ( - 13 ) \pm 11}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- ( - 13 ) + 11}{2 \cdot 4}, a_{2} = \frac{- ( - 13 ) - 11}{2 \cdot 4}

a = \frac{- ( - 13 ) + 11}{2 \cdot 4} : 3

a = \frac{- ( - 13 ) - 11}{2 \cdot 4} : \frac{1}{4}

The solutions to the quadratic equation are:

a = 3, a = \frac{1}{4}

- 13 - 5 x = - 5 x^{2}

y^{2} + 13 y + 42 = 0

x, 7 x^{2} + 3 x - 2 = 0

(2 (\frac{3}{2}) - 1) x^{2} + 4 x + 2 = 0

(x - 3) (x + 3) = 6 x - 14

What are the solutions to the equation 4a^2-13a+3=0 ?
The solutions to the equation 4a^2-13a+3=0 are a=3,a= 1/4
Find the zeros of 4a^2-13a+3=0
The zeros of 4a^2-13a+3=0 are a=3,a= 1/4