What are the solutions to the equation x^2-x=x+15 ?

The solutions to the equation x^2-x=x+15 are x=5,x=-3

Find the zeros of x^2-x=x+15

The zeros of x^2-x=x+15 are x=5,x=-3

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x^{2} - x = x + 15

x = 5, x = - 3

Solution steps

x^{2} - x = x + 15

Move

15

to the left side

x^{2} - x - 15 = x

Move

x

to the left side

x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

x = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

x = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

2 x^{2} + 3 x - 9 = 0

4 y^{2} + 16 y = 0

3 x^{2} + 5 x = - 2

x, 3 x^{2} + 6 x y = 0

x, 3 x^{2} + 2 x - 5 = 0

What are the solutions to the equation x^2-x=x+15 ?
The solutions to the equation x^2-x=x+15 are x=5,x=-3
Find the zeros of x^2-x=x+15
The zeros of x^2-x=x+15 are x=5,x=-3