What are the solutions to the equation 4p^2-20p+19=0 ?

The solutions to the equation 4p^2-20p+19=0 are p=(5+sqrt(6))/2 ,p=(5-sqrt(6))/2

Find the zeros of 4p^2-20p+19=0

The zeros of 4p^2-20p+19=0 are p=(5+sqrt(6))/2 ,p=(5-sqrt(6))/2

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4 p^{2} - 20 p + 19 = 0

p = \frac{5 + 6}{2}, p = \frac{5 - 6}{2}

Decimal Notation

p = 3.72474 \dots, p = 1.27525 \dots

Solution steps

4 p^{2} - 20 p + 19 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 19}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 19 = 46

p_{1, 2} = \frac{- ( - 20 ) \pm 4 6}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 20 ) + 4 6}{2 \cdot 4}, p_{2} = \frac{- ( - 20 ) - 4 6}{2 \cdot 4}

p = \frac{- ( - 20 ) + 4 6}{2 \cdot 4} : \frac{5 + 6}{2}

p = \frac{- ( - 20 ) - 4 6}{2 \cdot 4} : \frac{5 - 6}{2}

The solutions to the quadratic equation are:

p = \frac{5 + 6}{2}, p = \frac{5 - 6}{2}

j (x) = 6 x^{2} - 2 x + 4

x^{2} + 4 x + 5 = 0

(x + 5) (x - 8) = 0

5 z^{2} - 14 z - 3 = 0

2 x^{2} - x - 3

What are the solutions to the equation 4p^2-20p+19=0 ?
The solutions to the equation 4p^2-20p+19=0 are p=(5+sqrt(6))/2 ,p=(5-sqrt(6))/2
Find the zeros of 4p^2-20p+19=0
The zeros of 4p^2-20p+19=0 are p=(5+sqrt(6))/2 ,p=(5-sqrt(6))/2