What are the solutions to the equation 15x^2-8=14x ?

The solutions to the equation 15x^2-8=14x are x= 4/3 ,x=-2/5

Find the zeros of 15x^2-8=14x

The zeros of 15x^2-8=14x are x= 4/3 ,x=-2/5

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15 x^{2} - 8 = 14 x

x = \frac{4}{3}, x = - \frac{2}{5}

Decimal Notation

x = 1.33333 \dots, x = - 0.4

Solution steps

15 x^{2} - 8 = 14 x

Move

14 x

to the left side

15 x^{2} - 8 - 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

15 x^{2} - 14 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 15 ( - 8 )}{2 \cdot 15}

(- 14)^{2} - 4 \cdot 15 (- 8) = 26

x_{1, 2} = \frac{- ( - 14 ) \pm 26}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 26}{2 \cdot 15}, x_{2} = \frac{- ( - 14 ) - 26}{2 \cdot 15}

x = \frac{- ( - 14 ) + 26}{2 \cdot 15} : \frac{4}{3}

x = \frac{- ( - 14 ) - 26}{2 \cdot 15} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{2}{5}

u^{2} - 12 u

4 x^{2} - 5 = 11 x

x^{2} - 19 = 30

5 (x - 3)^{2} = 45

- x^{2} + 8 x = 16

What are the solutions to the equation 15x^2-8=14x ?
The solutions to the equation 15x^2-8=14x are x= 4/3 ,x=-2/5
Find the zeros of 15x^2-8=14x
The zeros of 15x^2-8=14x are x= 4/3 ,x=-2/5